IPL 2019: Rohit Sharma's brave call that bagged them the title
New Delhi : After seven weeks of quality cricket, the final match got locked between the Chennai Super Kings and Mumbai Indians on Sunday. Both the teams had reached the spot like champions and it was difficult to understand who will end up winning the game. And the thrilling last ball decided proved the assumption correct.
Winning the toss, Mumbai Indians skipper Rohit Sharma decided to bat first against the Chennai Super Kings. Mumbai Indians got off to a fantastic start as Quinton de Kock seemed to be in a great knick. The South African collected 20 runs off one over of Deepak Chahar.
Most captains would remove the bowler from the attack who had just got a poor start, but then there are captains like Mahendra Singh Dhoni who brought back Chahar from the other end. The pacer did not disappoint as he picked up crucial wicket of Rohit Sharma to derail MI innings.
Struggling from that point, Mumbai Indians managed to score 149 against the Men in Yellow.
CSK started the chase with a bang as Faf du Plessis and Shane Watson gave their team a desired quick start. Then Rahul Chahar got the wicket of Suresh Raina to give MI a real chance.
Jasprit Bumrah delivered for his team by picking the wicket of Ambati Rayudu. This brought MS Dhoni to the crease earlier than he would have liked. When MS Dhoni got run out while trying to pinch a run off an overthrow, the match turned on its head.
Taking the battle on his shoulder, Shane Watson took the game close to 9 runs in the final over. Now, at this point Rohit Sharma had to make a tough call as Shane Watson had crushed Malinga in his previous spell and with 9 runs to defend a new bowler would have been risky.
Rohit went for the experienced bowler and placed Malinga on to the attack. Playing with his experience, he bowled a slower Yorker on the last ball to defend 1 run from tie; MI won the match by one run to become the first team to lift the IPL trophy for the fourth time.